Gas is enclosed in a cylinder at 273 K and 1 atm pressure condition . At what temperature , the volume of enclosed gas is reduced to `1//8^(th)` of its initial volume. Pressure is kept constant throughout.

Explanation

To solve the problem step by step, we will use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is held constant.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Initial Temperature (T1) = 273 K
- Initial Volume (V1) = V1 (let's assume it as V1 for calculation)
- Final Volume (V2) = 1/8 of V1 = V1/8
...