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Gas is enclosed in a cylinder at 273 K a...

Gas is enclosed in a cylinder at 273 K and 1 atm pressure condition . At what temperature , the volume of enclosed gas is reduced to `1//8^(th)` of its initial volume. Pressure is kept constant throughout.

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To solve the problem step by step, we will use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is held constant. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Initial Temperature (T1) = 273 K - Initial Volume (V1) = V1 (let's assume it as V1 for calculation) - Final Volume (V2) = 1/8 of V1 = V1/8 ...
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Knowledge Check

  • Pressure remaining constant, at what temperature the volume of a gas will be double of its volume at 0^@C ?

    A
    `100^@C`
    B
    `546^@C`
    C
    `273 K`
    D
    `546 K`

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