A uniform solid sphere of mass M and radius R rolls down an inclined plane making an angle `theta` with the horizontal without slipping. Show that the acceleration of the sphere is `(5)/(7)gsin theta`. [ Given: moment of inertia of the sphere is `(2)/(5) MR^(2)` ]

The rotational kinetic energy of a solid sphere of mass 3 kg and radius 0.2 rolling down an inclined plane of height 7 m is

The ratio of the acceleration for a solid sphere (mass m and radius R ) rolling down an incline of angle theta without slipping and slipping down the incline without rolling is

A disc of mass M and radius R is rolling without slipping down an inclined plane. Show that the acceleration of the centre of mass of the disc is (2)/(3) g sin theta . Given angle of inclination of the plane is theta and moment of inertia of the disc is (MR^(2))/(2) .

A disc of mass M and radius R is rolling without slipping down ay inclined plane. Show that the acceleration of the centre of mass of the disc is 2/3 g sin theta . Given, angle of inclination of the plane is theta and moment of inertia .of the disc is (MR^2)/2