Home
Class 9
PHYSICS
A ball is thrown vertically upwards. It ...

A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be `10 "m s"^(-2)` ?, find the initial velocity of the ball

Text Solution

AI Generated Solution

To find the initial velocity of a ball thrown vertically upwards that reaches a height of 20 m before returning to the ground, we can use the third equation of motion. Here’s a step-by-step solution: ### Step 1: Identify the known values - Maximum height (h) = 20 m - Acceleration due to gravity (g) = 10 m/s² (acting downwards) - Final velocity (v) at the maximum height = 0 m/s (the ball stops momentarily at the highest point) ### Step 2: Write the third equation of motion ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAWS OF MOTION

    ICSE|Exercise EXAMPLES|24 Videos
  • LAWS OF MOTION

    ICSE|Exercise EXERCISE - 3(A)|19 Videos
  • LAWS OF MOTION

    ICSE|Exercise TOPIC 3 (3 Marks Questions ) |7 Videos
  • ICSE ANNUAL EXAMINATION -2020

    ICSE|Exercise SECTION-II|45 Videos
  • LIGHT

    ICSE|Exercise TOPIC 2 Spherical Mirrors (4 Marks Questions )|9 Videos

Similar Questions

Explore conceptually related problems

A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be 10 "m s"^(-2) ?, find the final velocity of ball on reaching the ground

A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be 10 "m s"^(-2) ?, find the total time of journey of ball.

A ball is thrown vertically upwards. It goes to a height 19.6 m and then comes back to the ground, Find the initial velocity of the ball . Take g = 9.8 m s^(-2)

A ball is thrown vertically upwards. It goes to a height 19.6 m and then comes back to the ground, Find the final velocity of the ball when it strikes the ground. Take g = 9.8 m s^(-2)

A ball is thrown vertically upwards. It returns 6 s later. Calculate the greatest height reached by the ball

A ball is thrown vertically upwards. It was observed at a height h twice after a time interval Deltat . The initial velocity of the ball is

A ball is thrown vertically upwards with a velocity of 10 ms^(-1) . It returns to the ground with a velocity of 9 ms^(-1) . If g=9.8 ms^(-2) , then the maximum height attained by the ball is nearly (assume air resistance to be uniform)

A ball of mass m is thrown straight up. It goes to a maximum height and then returns. Finally it strikes ground. In the whole process.

A ball is thrown upwards . Its height varies with time as shown in figure. If the acceleration due to gravity is 7.5 m//s^(2) , then the height h is

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.