Home
Class 9
PHYSICS
A ball is thrown vertically upwards from...

A ball is thrown vertically upwards from the top of a tower with an initial velocity of `19.6 "m s"^(-1)`. The ball reaches the ground after 5 s. Calculate the height of the tower . Take `g= 9.8 "ms"^(-2)` ?

Text Solution

AI Generated Solution

To solve the problem of finding the height of the tower from which a ball is thrown vertically upwards, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Initial velocity (u) = 19.6 m/s (upward) - Time taken to reach the ground (t) = 5 s - Acceleration due to gravity (g) = -9.8 m/s² (downward) ...
Promotional Banner

Topper's Solved these Questions

  • LAWS OF MOTION

    ICSE|Exercise EXAMPLES|24 Videos

  • LAWS OF MOTION

    ICSE|Exercise EXERCISE - 3(A)|19 Videos

  • LAWS OF MOTION

    ICSE|Exercise TOPIC 3 (3 Marks Questions ) |7 Videos

  • ICSE ANNUAL EXAMINATION -2020

    ICSE|Exercise SECTION-II|45 Videos

  • LIGHT

    ICSE|Exercise TOPIC 2 Spherical Mirrors (4 Marks Questions )|9 Videos

Similar Questions

Explore conceptually related problems

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m s^(-1) . The ball reaches the ground after 5s. Calculate the height of the tower .

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 "m s"^(-1) . The ball reaches the ground after 5 s. Calculate the velocity of the ball on reaching the ground.Take g= 9.8 "ms"^(-2) ?

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A body is dropped from the top of a tower. It acquires a velocity 20 m s^(-1) on reaching the ground. Calculate the height of the tower. (Take g = 10 m s^(-2) )

A ball is thrown vertically upward from the top of a tower with a speed of 100 m/s. It strikes the pond near the base of the tower after 25 second. The height of the tower is

A ball is thrown vertically upwards from the top of a building of height 24.5 m with an initial velocity 19.6 m s^(-1) . Taking g = 9.8 ms, calculate : the velocity with which it will strike the ground .

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown vertically up from the top of a tower with velocity 10 m//s . It reaches the ground in 5s. Calculate the following - (a) Height of tower (b) Striking velocity of particle at ground (c ) Distance traversed by particle. (d) Average speed & average velocity of particle.