The area of base of a cylindrical vessel is `300 "cm"^2`.
Water (density= `1000 "kg/m"^3`) is poured into it up to a depth of 6 cm. Calculate the thrust of water on the base. `(g = 10 "m s"^(-2))`.

Explanation

To solve the problem step by step, we will calculate the thrust of water on the base of the cylindrical vessel using the given data.

### Step 1: Identify the given data
- Area of the base of the cylindrical vessel, \( A = 300 \, \text{cm}^2 \)
- Density of water, \( \rho = 1000 \, \text{kg/m}^3 \)
- Height of water, \( h = 6 \, \text{cm} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)

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