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Assuming the density of air to be 1.295 ...

Assuming the density of air to be `1.295 "kg m"^(-3)`, find the fall in barometric height in mm of Hg at a height of `107`m above the sea level. Take density of mercury = `13.6 xx 10^3 "kg m"^(-3)` .

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To solve the problem of finding the fall in barometric height in mm of Hg at a height of 107 m above sea level, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Data:** - Density of air, \( \rho_{air} = 1.295 \, \text{kg/m}^3 \) - Density of mercury, \( \rho_{Hg} = 13.6 \times 10^3 \, \text{kg/m}^3 \) - Height above sea level, \( h = 107 \, \text{m} \) ...
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Knowledge Check

  • Torricelli's barometer used mercury but pascal duplicated it using French wine of density 984 kg m^(-3) . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury =1.36xx10^(3) kg m^(-3) )

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