The density of ice is `0.92 "g cm"^(-3)` and that of sea water is `1.025 "g cm"^(-3)`. Find the total volume of an iceberg which floats with its volume `800 "cm"^(-3)` above water.

Explanation

To find the total volume of the iceberg that floats with a volume of 800 cm³ above the water, we can follow these steps:

### Step 1: Understand the problem
We know the density of ice (ρ_ice = 0.92 g/cm³) and the density of seawater (ρ_water = 1.025 g/cm³). We are given that the volume of the iceberg above water is 800 cm³. We need to find the total volume (V) of the iceberg.

### Step 2: Set up the buoyancy equation
According to Archimedes' principle, the buoyant force acting on the iceberg is equal to the weight of the water displaced by the submerged part of the iceberg.

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