Home
Class 12
PHYSICS
A foce acts on a 30g particle in such a ...

A foce acts on a 30g particle in such a way that the position of the particle as a function of time is given by
`x=3t-4t^(2)+t^(3)`, where x is in metre and t in second. The work done during the first 4s is

A

5700mJ

B

4500mJ

C

4900mJ

D

5280mJ

Text Solution

Verified by Experts

The correct Answer is:
d
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .

Knowledge Check

  • The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

    A
    a. 4 m
    B
    b. 8 m
    C
    c. 12 m
    D
    d. 16 m
  • Similar Questions

    Explore conceptually related problems

    Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

    Force acting on a particle is given by F=(A-x)/(Bt) , where x is in metre and t is in seconds. The dimensions of B is -

    The position x of a particle moving along x - axis at time (t) is given by the equation t=sqrtx+2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds

    The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

    A particle moves along a straight line and its position as a function of time is given by x = t6(3) - 3t6(2) +3t +3 , then particle

    The equation of motion of a particle starting at t=0 is given by x=5sin(20t+π/3) , where x is in centimeter and t is in second. When does the particle come to rest for the second time?

    The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is