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Electric field at centre O of semicircul...

Electric field at centre O of semicircule of radius 'a' having linear charge density `lambda` given is given by

A

`(2 lambda)/(in_(0) a)`

B

`(lambda pi)/(in_(0) a)`

C

`(lambda)/(2 pi in_(0) a)`

D

`(lambda)/(pi in_(0) a)`

Text Solution

Verified by Experts

The correct Answer is:
C

Electric field at `O = (2K lambda)/(a) sin (alpha//2)`
`= (2 lambda)/(4 pi in_(0) a) "sin" (pi)/(2) = (lambda)/(2 pi in_(0) a)`
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