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If the equation (1+m)x^(2)-2(1+3m)x+(1-8...

If the equation `(1+m)x^(2)-2(1+3m)x+(1-8m)=0` where `m epsilonR~{-1}`, has atleast one root is negative, then

A

`m epsilon(-oo,-1)`

B

`m epsilon (-1/8,oo)`

C

`m epsilon(-1-1/8)`

D

`m epsilonR`

Text Solution

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The correct Answer is:
To determine the values of \( m \) for which the quadratic equation \[ (1+m)x^2 - 2(1+3m)x + (1-8m) = 0 \] has at least one negative root, we will analyze the conditions under which this occurs. ### Step 1: Identify coefficients First, we identify the coefficients of the quadratic equation in the standard form \( ax^2 + bx + c = 0 \): - \( a = 1 + m \) - \( b = -2(1 + 3m) \) - \( c = 1 - 8m \) ### Step 2: Conditions for roots For a quadratic equation to have at least one negative root, we need to ensure: 1. The sum of the roots \( \alpha + \beta > 0 \) 2. The product of the roots \( \alpha \beta < 0 \) 3. The discriminant \( D \geq 0 \) (to ensure real roots) ### Step 3: Calculate the sum of the roots The sum of the roots is given by: \[ \alpha + \beta = -\frac{b}{a} = \frac{2(1 + 3m)}{1 + m} \] For this to be greater than 0: \[ \frac{2(1 + 3m)}{1 + m} > 0 \] ### Step 4: Analyze the inequality for the sum of the roots The inequality \( 2(1 + 3m) > 0 \) implies: \[ 1 + 3m > 0 \implies m > -\frac{1}{3} \] The denominator \( 1 + m > 0 \) implies: \[ m > -1 \] Thus, we have: \[ m > -\frac{1}{3} \quad \text{and} \quad m > -1 \] ### Step 5: Calculate the product of the roots The product of the roots is given by: \[ \alpha \beta = \frac{c}{a} = \frac{1 - 8m}{1 + m} \] For this to be less than 0: \[ \frac{1 - 8m}{1 + m} < 0 \] ### Step 6: Analyze the inequality for the product of the roots The numerator \( 1 - 8m < 0 \) implies: \[ 1 < 8m \implies m > \frac{1}{8} \] The denominator \( 1 + m > 0 \) implies: \[ m > -1 \] Thus, we have: \[ m > \frac{1}{8} \quad \text{and} \quad m > -1 \] ### Step 7: Calculate the discriminant The discriminant \( D \) is given by: \[ D = b^2 - 4ac = (-2(1 + 3m))^2 - 4(1 + m)(1 - 8m) \] Calculating \( D \): \[ D = 4(1 + 3m)^2 - 4(1 + m)(1 - 8m) \] Setting \( D \geq 0 \): \[ 4(1 + 3m)^2 - 4(1 + m)(1 - 8m) \geq 0 \] ### Step 8: Solve the discriminant inequality This simplifies to: \[ (1 + 3m)^2 - (1 + m)(1 - 8m) \geq 0 \] After simplification, we can find the values of \( m \) that satisfy this condition. ### Conclusion After analyzing all conditions, we find that the values of \( m \) that satisfy all the inequalities are: \[ m \in (-\infty, -1) \cup \left(-\frac{1}{8}, \infty\right) \] Thus, the final answer is: \[ m \in (-\infty, -1) \cup \left(-\frac{1}{8}, \infty\right) \]
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