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f:R->R is defined as f(x)=2x+|x| then f(...

`f:R->R` is defined as `f(x)=2x+|x|` then `f(3x)-f(-x)-4x=`

A

a) `f(x)`

B

b) `-f(x)`

C

c) `f(-x)`

D

d) `2f(x)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to evaluate the expression \( f(3x) - f(-x) - 4x \) where the function \( f(x) = 2x + |x| \). ### Step-by-Step Solution: 1. **Define the function**: \[ f(x) = 2x + |x| \] 2. **Calculate \( f(3x) \)**: \[ f(3x) = 2(3x) + |3x| = 6x + 3|x| \] 3. **Calculate \( f(-x) \)**: \[ f(-x) = 2(-x) + |-x| = -2x + |x| \] 4. **Substitute \( f(3x) \) and \( f(-x) \) into the expression**: \[ f(3x) - f(-x) - 4x = (6x + 3|x|) - (-2x + |x|) - 4x \] 5. **Simplify the expression**: - First, distribute the negative sign: \[ = 6x + 3|x| + 2x - |x| - 4x \] - Combine like terms: \[ = (6x + 2x - 4x) + (3|x| - |x|) = 4x + 2|x| \] 6. **Factor out the common term**: \[ = 2(2x + |x|) \] 7. **Recognize that \( 2(2x + |x|) \) is \( 2f(x) \)**: \[ = 2f(x) \] ### Final Result: Thus, we find that: \[ f(3x) - f(-x) - 4x = 2f(x) \] ### Conclusion: The answer is \( 2f(x) \).

To solve the problem, we need to evaluate the expression \( f(3x) - f(-x) - 4x \) where the function \( f(x) = 2x + |x| \). ### Step-by-Step Solution: 1. **Define the function**: \[ f(x) = 2x + |x| \] ...
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ARIHANT MATHS ENGLISH-SETS, RELATIONS AND FUNCTIONS -Exercise (Single Option Correct Type Questions)
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  11. Let R be a relation defined by R = {(a, b) : a ge b}, where a and b a...

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  12. If the sets A and B are defined are defined as A={(x,y):y=e^x, x in R}...

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  13. If function f:AtoB is a bijective , then f^(-1) of is

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  14. If f(y) = (y)/(sqrt(1-y^(2))), g(y) = (y)/(sqrt(1+y^(2))), then (fog) ...

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  15. f:R->R is defined as f(x)=2x+|x| then f(3x)-f(-x)-4x=

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  16. Let R and S be two non-void relations on a set A. Which of the followi...

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