Find a three digit numberwhose consecutive digits form a GP. If we subtract 792 from this number, we get a number consisting of the same digits written in the reverse order. Now, if we increase the second digit of the required number by 2, then the resulting digits will form an AP.

Explanation

To solve the problem step by step, we need to find a three-digit number whose consecutive digits form a geometric progression (GP) and satisfy the conditions given in the question.

### Step 1: Define the digits of the number
Let the three-digit number be represented as \( ABC \), where:
- \( A \) is the first digit (hundreds place)
- \( B \) is the second digit (tens place)
- \( C \) is the third digit (units place)

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