If pth, qth and rth terms of a HP be respectively`a,b` and `c`, has prove that `(q-r)bc+(r-p)ca+(p-q)ab=0`.

Explanation

To prove that \((q - r)bc + (r - p)ca + (p - q)ab = 0\) given that the \(p\)th, \(q\)th, and \(r\)th terms of a Harmonic Progression (HP) are \(a\), \(b\), and \(c\) respectively, we can follow these steps:

### Step 1: Understand the relationship between HP and AP
The terms of a Harmonic Progression can be related to an Arithmetic Progression (AP). If \(a\), \(b\), and \(c\) are the \(p\)th, \(q\)th, and \(r\)th terms of a HP, then their reciprocals \(\frac{1}{a}\), \(\frac{1}{b}\), and \(\frac{1}{c}\) are the \(p\)th, \(q\)th, and \(r\)th terms of an AP.

### Step 2: Write the terms of the corresponding AP
Let \(A\) be the first term and \(D\) be the common difference of the corresponding AP. We can express the terms as follows:
- \(\frac{1}{a} = A + (p-1)D\) (1)
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