When the ninth term of an AP is divided by its second term we get 5 as the quotient, when the thirteenth term ia devided ny sixth term the quotient is 2 and the remainderis 5, then the seonnd term is

Explanation

To solve the problem step by step, let's denote the first term of the arithmetic progression (AP) as \( A \) and the common difference as \( D \).

### Step 1: Set up the equations based on the given conditions.

1. **Condition 1**: The ninth term divided by the second term gives a quotient of 5.
- The ninth term of the AP is given by:
\[
T_9 = A + 8D
...