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Let A(1),A(2),A(3),"......."A(m) be arit...

Let `A_(1),A_(2),A_(3),"......."A_(m)` be arithmetic means between `-3` and 828 and `G_(1),G_(2),G_(3),"......."G_(n)` be geometric means between 1 and 2187. Produmt of geometrimc means is `3^(35)` and sum of arithmetic means is 14025.
The valjue of n is

A

45

B

30

C

25

D

10

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To solve the problem step by step, let's break it down into manageable parts. ### Step 1: Understanding the Problem We have two sets of means: 1. Arithmetic means \( A_1, A_2, A_3, \ldots, A_m \) between -3 and 828. 2. Geometric means \( G_1, G_2, G_3, \ldots, G_n \) between 1 and 2187. We are given: - The product of the geometric means is \( 3^{35} \). - The sum of the arithmetic means is 14025. We need to find the value of \( n \). ### Step 2: Finding the Number of Arithmetic Means The arithmetic means can be calculated using the formula for the sum of an arithmetic series. The number of arithmetic means \( m \) between two numbers \( a \) and \( b \) can be calculated as follows: \[ \text{Sum} = \frac{m + 2}{2} \times \text{(first term + last term)} \] Here, the first term is -3 and the last term is 828. Thus, we have: \[ 14025 = \frac{m + 2}{2} \times (-3 + 828) \] Calculating \( -3 + 828 = 825 \): \[ 14025 = \frac{m + 2}{2} \times 825 \] ### Step 3: Solving for \( m \) Now, we can rearrange the equation to solve for \( m \): \[ 14025 = \frac{m + 2}{2} \times 825 \] Multiplying both sides by 2: \[ 28050 = (m + 2) \times 825 \] Now, divide both sides by 825: \[ m + 2 = \frac{28050}{825} \] Calculating \( \frac{28050}{825} = 34 \): \[ m + 2 = 34 \] Thus, we find: \[ m = 34 - 2 = 32 \] ### Step 4: Finding the Number of Geometric Means Next, we use the information about the geometric means. The product of the geometric means is given by: \[ \text{Product} = G_1 \cdot G_2 \cdot \ldots \cdot G_n = \left( \frac{1 \cdot 2187}{2} \right)^{n} \] We know that \( 2187 = 3^7 \), so we can express the product as: \[ 3^{35} = (1 \cdot 2187)^{n/2} = (1 \cdot 3^7)^{n/2} \] This simplifies to: \[ 3^{35} = 3^{7n/2} \] ### Step 5: Equating the Exponents Since the bases are the same, we can equate the exponents: \[ 35 = \frac{7n}{2} \] Multiplying both sides by 2: \[ 70 = 7n \] Now, dividing both sides by 7: \[ n = 10 \] ### Final Answer The value of \( n \) is \( \boxed{10} \). ---

To solve the problem step by step, let's break it down into manageable parts. ### Step 1: Understanding the Problem We have two sets of means: 1. Arithmetic means \( A_1, A_2, A_3, \ldots, A_m \) between -3 and 828. 2. Geometric means \( G_1, G_2, G_3, \ldots, G_n \) between 1 and 2187. We are given: ...
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