Home
Class 12
MATHS
The lengths of the sides of a traingle a...

The lengths of the sides of a traingle are `log_(10)12,log_(10)75andlog_(10)n`, where `n in N`. If a and b are the least ad greatest values of n respectively. The value of b-a is divisible by

A

221

B

222

C

223

D

224

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine the values of \( n \) such that the lengths of the sides of the triangle, given as \( \log_{10} 12 \), \( \log_{10} 75 \), and \( \log_{10} n \), satisfy the triangle inequality conditions. ### Step 1: Define the variables Let: - \( x = \log_{10} 12 \) - \( y = \log_{10} 75 \) - \( z = \log_{10} n \) ### Step 2: Apply the triangle inequality We know that for any triangle, the sum of the lengths of any two sides must be greater than the length of the third side. Therefore, we can write the following inequalities: 1. \( x + y > z \) 2. \( x + z > y \) 3. \( y + z > x \) ### Step 3: Solve the first inequality From the first inequality \( x + y > z \): \[ \log_{10} 12 + \log_{10} 75 > \log_{10} n \] Using the property of logarithms \( \log_{10} a + \log_{10} b = \log_{10} (a \cdot b) \): \[ \log_{10} (12 \cdot 75) > \log_{10} n \] Calculating \( 12 \cdot 75 = 900 \): \[ \log_{10} 900 > \log_{10} n \] This implies: \[ n < 900 \] ### Step 4: Solve the second inequality From the second inequality \( x + z > y \): \[ \log_{10} 12 + \log_{10} n > \log_{10} 75 \] Using logarithmic properties: \[ \log_{10} (12n) > \log_{10} 75 \] This implies: \[ 12n > 75 \quad \Rightarrow \quad n > \frac{75}{12} = 6.25 \] ### Step 5: Solve the third inequality From the third inequality \( y + z > x \): \[ \log_{10} 75 + \log_{10} n > \log_{10} 12 \] Using logarithmic properties: \[ \log_{10} (75n) > \log_{10} 12 \] This implies: \[ 75n > 12 \quad \Rightarrow \quad n > \frac{12}{75} = 0.16 \] ### Step 6: Combine the inequalities From the inequalities we have: 1. \( n < 900 \) 2. \( n > 6.25 \) 3. \( n > 0.16 \) The most restrictive conditions are: \[ 6.25 < n < 900 \] ### Step 7: Determine the natural number values of \( n \) Since \( n \) must be a natural number, the smallest integer greater than 6.25 is 7, and the largest integer less than 900 is 899. Thus: - The least value \( a = 7 \) - The greatest value \( b = 899 \) ### Step 8: Calculate \( b - a \) Now, we calculate: \[ b - a = 899 - 7 = 892 \] ### Step 9: Check divisibility We need to find out if \( 892 \) is divisible by any of the options provided. ### Final Answer The value of \( b - a \) is \( 892 \), and it is divisible by \( 23 \).
Promotional Banner

Topper's Solved these Questions

  • LOGARITHM AND THEIR PROPERTIES

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 1|5 Videos
  • LOGARITHM AND THEIR PROPERTIES

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 2|5 Videos
  • LIMITS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 6|5 Videos
  • MATHEMATICAL INDUCTION

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|2 Videos

Similar Questions

Explore conceptually related problems

If a and b are the greatest values of ""^(2n)C_(r)and""^(2n-1)C_(r) respectively. Then,

If log_(10)5=a and log_(10)3=b ,then

If log_6a+log_6b+log_6c=6 ,where a,b,c, in N and a,b,c are in GP and b-a is a square of an integer, then the value of a+b-c is

The domain of definition of f(x)=log_(10) log_(10)…..log_(10)x n times, is

The value of x satisfying the equation 2log_(10)x - log_(10) (2x-75) = 2 is

The value of N satisfying log_(a)[1+log_(b){1+log_(c)(1+log_(p)N)}]=0 is

If x,yinR^+ and log_10(2x)+log_10y=2 , log_10x^2-log_10(2y)=4 and x+y=m/n ,Where m and n are relative prime , the value of m-3n^(6) is

log_10⁡ a + log_10 ⁡b = log_10⁡ (a+b)

Given log_(10)2 = a and log_(10)3 = b . If 3^(x+2) = 45 , then the value of x in terms of a and b is-

the value of e^(log_(10)tan1^@+log_(10)tan2^@+log_(10)tan3^@....+log_(10)tan89^@