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10^(logp(logq(logr(x))))=1 and logq(logr...

`10^(log_p(log_q(log_r(x))))=1` and `log_q(log_r(log_p(x)))=0`, then 'p' is equals a. `r^(q/r)` b. `rq` c. 1 d. `r^(r/q)`

A

`log _q{log_r(log_px)}=0`.

B

rq

C

1

D

`r^(r//p)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equations given in the problem, we will follow a systematic approach using logarithmic properties. ### Given: 1. \( 10^{\log_p(\log_q(\log_r(x)))} = 1 \) 2. \( \log_q(\log_r(\log_p(x))) = 0 \) ### Step 1: Analyze the first equation From the first equation, we know that: \[ 10^{\log_p(\log_q(\log_r(x)))} = 1 \] Since \( 10^0 = 1 \), we can equate the exponent to zero: \[ \log_p(\log_q(\log_r(x))) = 0 \] ### Step 2: Convert the logarithmic equation Using the property of logarithms, we know that: \[ \log_p(a) = 0 \Rightarrow a = p^0 = 1 \] Thus, we have: \[ \log_q(\log_r(x)) = 1 \] ### Step 3: Analyze the second equation Now, let's analyze the second equation: \[ \log_q(\log_r(\log_p(x))) = 0 \] Again, using the property of logarithms: \[ \log_q(a) = 0 \Rightarrow a = q^0 = 1 \] This gives us: \[ \log_r(\log_p(x)) = 1 \] ### Step 4: Convert this logarithmic equation Using the property of logarithms again: \[ \log_r(b) = 1 \Rightarrow b = r^1 = r \] Thus, we have: \[ \log_p(x) = r \] ### Step 5: Solve for \( x \) Using the property of logarithms: \[ \log_p(x) = r \Rightarrow x = p^r \] ### Step 6: Substitute \( x \) back into the first equation Now we substitute \( x = p^r \) into the equation derived from the first equation: \[ \log_q(\log_r(x)) = 1 \] Substituting \( x \): \[ \log_q(\log_r(p^r)) = 1 \] ### Step 7: Calculate \( \log_r(p^r) \) Using the property of logarithms: \[ \log_r(p^r) = r \cdot \log_r(p) \] Thus: \[ \log_q(r \cdot \log_r(p)) = 1 \] ### Step 8: Solve for \( p \) Now we know: \[ \log_q(r \cdot \log_r(p)) = 1 \Rightarrow r \cdot \log_r(p) = q \] From this, we can express \( \log_r(p) \): \[ \log_r(p) = \frac{q}{r} \] ### Step 9: Convert back to \( p \) Using the property of logarithms: \[ p = r^{\frac{q}{r}} \] ### Conclusion Thus, we find that: \[ p = r^{\frac{q}{r}} \] ### Final Answer The correct option is: **a. \( r^{\frac{q}{r}} \)**
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