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Given a^2+b^2=c^2. Prove that log(b+c)...

Given `a^2+b^2=c^2`. Prove that
`log_(b+c)a+log_(c-b)a=2 log_(c+b)a.log_(c-b)a,forallagt0,ane1`
`c-bgt0`,`c+bgt0`
`c-bne1`,`c+bne1`.

Text Solution

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The correct Answer is:
A=RHS
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