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If z^3+(3+2i)z+(-1+i a)=0 has one real r...

If `z^3+(3+2i)z+(-1+i a)=0` has one real roots, then the value of `a` lies in the interval `(a in R)` `(-2,1)` b. `(-1,0)` c. `(0,1)` d. `(-2,3)`

A

(-2,1)

B

(-1,0)

C

(0,1)

D

(-2,3)

Text Solution

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The correct Answer is:
A, B, D
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