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Find dy/dx if y= sin^4x...

Find `dy/dx if y= sin^4x`

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To find \(\frac{dy}{dx}\) for the function \(y = \sin^4 x\), we will use the chain rule. Here’s a step-by-step solution: ### Step 1: Identify the function We have: \[ y = \sin^4 x \] This can be viewed as a composition of functions where \(u = \sin x\) and \(y = u^4\). ### Step 2: Apply the chain rule According to the chain rule: \[ \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \] ### Step 3: Differentiate the outer function First, we differentiate \(y = u^4\): \[ \frac{dy}{du} = 4u^3 \] ### Step 4: Differentiate the inner function Next, we differentiate \(u = \sin x\): \[ \frac{du}{dx} = \cos x \] ### Step 5: Combine the derivatives Now, substitute \(u = \sin x\) back into the derivative: \[ \frac{dy}{dx} = 4(\sin x)^3 \cdot \cos x \] ### Final Result Thus, the derivative \(\frac{dy}{dx}\) is: \[ \frac{dy}{dx} = 4 \sin^3 x \cos x \] ---
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ARIHANT MATHS ENGLISH-LIMITS-Exercise (Single Integer Answer Type Questions)
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  13. Find dy/dx if y= sin^4x

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