Let`f(x)=x^(2)+xg'(1)+g''(2) and g(x)=x^(2)+xf'(2)+f''(3).` Then

Let f(x)=3x^(2)+4xg'(1)+g''(2) and, g(x)=2x^(2)+3xf'(2)+f''(3)" for all "x in R. Then,

f(x)=x^(2)+xg'(1)+g''(2)and g(x)=f(1)x^(2)+xf'(x)+f'(x). The domain of the function sqrt((f(x))/(g(x))) is

f(x)=x^(2)+xg'(1)+g''(2)and g(x)=f(1)x^(2)+xf'(x)+f'(x). The value of f(3) is

f(x)=x^(2)+xg'(1)+g''(2)and g(x)=f(1)x^(2)+xf'(x)+f'(x). The value of g(0) is

Let f (x) and g (x) be two differentiable functions, defined as: f (x)=x ^(2) +xg'(1)+g'' (2) and g (x)= f(1)x^(2) +x f' (x)+ f''(x). The number of integers in the domain of the function F(x)= sqrt(-(f(x))/(g (x)))+sqrt(3-x) is:

Let f(x)=x^2+xg^2(1)+g^''(2) and g(x)=f(1).x^2+xf'(x)+f''(x), then find f(x) and g(x).

Let f (x) and g (x) be two differentiable functions, defined as: f (x)=x ^(2) +xg'(1)+g'' (2) and g (x)= f (1) x^(2) +x f' (x)+ f''(x). The value of f (1) +g (-1) is:

Let f (x)=(x+1) (x+2) (x+3)…..(x+100) and g (x) =f (x) f''(x) -f'(x) ^(2). Let n be the numbers of real roots of g(x) =0, then:

Let f and g be two differentiable functins such that: f (x)=g '(1) sin x+ (g'' (2) -1) x g (x) = x^(2) -f'((pi)/(2)) x+ f'(-(pi)/(2)) If phi (x) =f ^(-1) (x) then phi'((pi)/(2) +1) equals to :

Let f and g be two differentiable functins such that: f (x)=g '(1) sin x+ (g'' (2) -1) x g (x) = x^(2) -f'((pi)/(2)) x+ f'(-(pi)/(2)) The number of solution (s) of the equation f (x) = g (x) is/are :