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Left hand derivative and right hand deri...

Left hand derivative and right hand derivative of a function `f(x)` at a point `x=a` are defined as
`f'(a^-)=lim_(hrarr0^(+))(f(a)-f(a-h))/(h)`
`=lim_(hrarr0^(+))(f(a+h)-f(a))/(h)`
`andf'(a^(+))=lim_(hrarr0^(+))(f(a+h)-f(a))/(h)`
`=lim_(hrarr0^(+))(f(a)-f(a+h))/(h)`
`=lim_(hrarr0^(+)) (f(a)-f(x))/(a-x)` respectively.
Let `f` be a twice differentiable function. We also know that derivative of a even function is odd function and derivative of an odd function is even function.
If `f` is even function, which of the following is right hand derivative of `f'` at `x=a?`

A

(a) `underset(hrarr0^(-))lim(f'(a)+f'(-a+h))/(-h)`

B

(b) `underset(hrarr0^(+))lim(f'(a)+f'(-a-h))/(h)`

C

(c) `underset(hrarr0^(-))lim(-f'(-a)+f'(-a-h))/(-h)`

D

(d) `underset(hrarr0^(+))lim(f'(a)+f'(-a+h))/(-h)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the right-hand derivative of the function \( f' \) at \( x = a \) given that \( f \) is an even function, we can follow these steps: ### Step 1: Understand the properties of even and odd functions Since \( f \) is an even function, we know that: \[ f(-x) = f(x) \quad \text{for all } x. \] The derivative of an even function, \( f' \), is an odd function. This means: \[ f'(-x) = -f'(x) \quad \text{for all } x. \] ### Step 2: Write the definition of the right-hand derivative The right-hand derivative of \( f' \) at \( x = a \) is defined as: \[ f''(a^+) = \lim_{h \to 0^+} \frac{f'(a + h) - f'(a)}{h}. \] ### Step 3: Substitute the property of the odd function Using the property of the odd function, we can express \( f'(a + h) \) in terms of \( f'(-a - h) \): \[ f'(a + h) = -f'(-a - h). \] Now, substitute this into the right-hand derivative definition: \[ f''(a^+) = \lim_{h \to 0^+} \frac{-f'(-a - h) - f'(a)}{h}. \] ### Step 4: Simplify the expression We can rewrite the limit: \[ f''(a^+) = \lim_{h \to 0^+} \frac{-f'(-a - h) + (-f'(-a))}{h}. \] This simplifies to: \[ f''(a^+) = \lim_{h \to 0^+} \frac{-f'(-a - h) + f'(-a)}{h}. \] ### Step 5: Recognize the limit as a derivative The expression we have is now in the form of a derivative: \[ f''(a^+) = \lim_{h \to 0^+} \frac{f'(-a) - f'(-a - h)}{h}. \] This is the definition of the derivative of \( f' \) at \( -a \), which can be expressed as: \[ f''(a^+) = -f''(-a). \] ### Conclusion Thus, the right-hand derivative of \( f' \) at \( x = a \) can be expressed as: \[ f''(a^+) = \lim_{h \to 0^+} \frac{f'(a) - f'(-a - h)}{h}. \] This matches with option B: \[ \text{B. } \lim_{h \to 0^+} \frac{f'(a) - f'(-a - h)}{h}. \]
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