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Let g(x) be the inverse of an invertible...

Let `g(x)` be the inverse of an invertible function `f(x),` which is differentiable for all real `xdot` Then `g^(f(x))` equals. `-(f^(x))/((f^'(x))^3)` (b) `(f^(prime)(x)f^(x)-(f^(prime)(x))^3)/(f^(prime)(x))` `(f^(prime)(x)f^(x)-(f^(prime)(x))^2)/((f^(prime)(x))^2)` (d) none of these

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The correct Answer is:
`-(f''(x))/((f'(x))^(3))`
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