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If the function f(x)=[3.5+bsin x] (where...

If the function f(x)=[3.5+bsin x] (where [.] denotes the greatest integer function) is an even function, the complete set of values of b is

A

(-0.5,0.5)

B

[-0.5,0.5]

C

(0,1)

D

[-1,1]

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the complete set of values of \( b \) such that the function \( f(x) = [3.5 + b \sin x] \) is an even function. ### Step-by-Step Solution: 1. **Understanding Even Functions**: An even function satisfies the condition \( f(-x) = f(x) \) for all \( x \). 2. **Setting Up the Equation**: For our function, we have: \[ f(-x) = [3.5 + b \sin(-x)] = [3.5 - b \sin x] \] Since \( \sin(-x) = -\sin x \). 3. **Equating the Two Expressions**: For \( f(x) \) to be even, we need: \[ [3.5 + b \sin x] = [3.5 - b \sin x] \] 4. **Analyzing the Greatest Integer Function**: The greatest integer function \( [x] \) returns the largest integer less than or equal to \( x \). Therefore, we need to consider the values of \( 3.5 + b \sin x \) and \( 3.5 - b \sin x \). 5. **Finding the Range of the Function**: - The term \( b \sin x \) varies between \( -|b| \) and \( |b| \) as \( \sin x \) varies from -1 to 1. - Thus, \( 3.5 + b \sin x \) will range from \( 3.5 - |b| \) to \( 3.5 + |b| \). 6. **Setting the Conditions for Equality**: For the two expressions to be equal under the greatest integer function, the ranges must overlap in such a way that they yield the same integer values. This means: \[ 3.5 - |b| < 4 \quad \text{and} \quad 3.5 + |b| > 3 \] 7. **Solving the Inequalities**: - From \( 3.5 - |b| < 4 \): \[ -|b| < 0.5 \implies |b| < 0.5 \] - From \( 3.5 + |b| > 3 \): \[ |b| > -0.5 \quad \text{(which is always true since } |b| \geq 0 \text{)} \] 8. **Combining the Results**: Therefore, the only condition we have is \( |b| < 0.5 \), which can be expressed as: \[ -0.5 < b < 0.5 \] 9. **Final Answer**: The complete set of values of \( b \) is: \[ b \in (-0.5, 0.5) \]
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