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If f(x)=3x-5, then f^(-1)(x) is given b...

If `f(x)=3x-5,` then `f^(-1)(x)` is given by `1/((3x-5))` is given by `((x+5))/3` does not exist because `f` is not one-one does not exist because `f` is not onto

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The correct Answer is:
`f^(-1)(x)=(x+5)/3`
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