Home
Class 12
MATHS
Let f(x)=sin^(23)x-cos^(22)xa n dg(x)=1+...

Let `f(x)=sin^(23)x-cos^(22)xa n dg(x)=1+1/2tan^(-1)|x|` . Then the number of values of `x` in the interval `[-10pi,8pi]` satisfying the equation `f(x)=sgn(g(x))` is __________

Text Solution

Verified by Experts

The correct Answer is:
3
Promotional Banner

Topper's Solved these Questions

  • FUNCTIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 1|5 Videos
  • FUNCTIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 2|6 Videos
  • ESSENTIAL MATHEMATICAL TOOLS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Integer Answer Type Questions)|3 Videos
  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

Similar Questions

Explore conceptually related problems

The number of values of x lying in the inteval (-2pi, 2pi) satisfying the equation 1+cos 10x cos 6x=2 cos^(2)8x+sin^(2)8x is equal to

The number of values of x in [-2pi, 2pi] which satisfy the equation "cosec x"=1+cot x is equal to

The number of real values of x satisfying the equation 3 sin^(-1)x +pi x-pi=0 is/are :

The number of solutions of x in the interval [-pi, pi] of the equation (1+cot267^(@)) (1+tan222^(@)) = sec^(2)x + cos^(2)x is

Number of solutions in the interval [0,2pi] satisfying the equation 8sin x=(sqrt(3))/(cos x)+1/(sin x) are a. 5 b. 6 c. 7 d. 8

Let f(x)=sin^(-1)x,g(x)=cos^(-1)x and h(x)=tan^(-1)x. For what complete interval of variation of x then following are true.

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is