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The domain of f(x)=sqrt(2{x}^2-3{x}+1), ...

The domain of `f(x)=sqrt(2{x}^2-3{x}+1),` where {.} denotes the fractional part in `[-1,1]` is (a) `[-1,1]-(1/(2),1)` (b)`[-1,-1/2]uu[(0,1)/2]uu{1}` (c)`[-1,1/2]` (d) `[-1/2,1]`

Text Solution

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The correct Answer is:
`[-1,-1/2] cup [0,1/2] cup {1}`
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