Home
Class 12
MATHS
Show that the normal at any point theta ...

Show that the normal at any point `theta` to the curve `x=acostheta+athetasintheta,\ y=asintheta-a\ thetacostheta` is at a constant distance from the origin.

A

2a unit from origin

B

a unit from origin

C

`(1)/(2)a` unit from origin

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 4|10 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 5|5 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 2|6 Videos
  • DIFFERENTIATION

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 10|4 Videos
  • ELLIPSE

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|27 Videos

Similar Questions

Explore conceptually related problems

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The length of normal at any point to the curve, y=c cosh(x/c) is

Find the equation of the normal to the curve x = acostheta and y = b sintheta at theta

Prove that all normals to the curve x=acost+a tsint ,\ \ y=asint-a tcost are at a distance a from the origin.

Find the length of normal to the curve x=a(theta+sintheta),y=a(1-costheta) at theta=pi/2dot

Find the length of normal to the curve x=a(theta+sintheta),y=a(1-costheta) at theta=pi/2dot

Find the slope of the normal to the curve x=a\ cos^3theta , y=a\ sin^3theta at theta=pi/4 .

Find the equations of the tangent and the normal to the curve x=a(theta+sintheta),\ \ y=a(1-costheta) at theta at indicated points.

Find the slopes of the tangent and the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at theta=pi//4

Find the slopes of the tangent and the normal to the curve x=a(theta-sintheta) , y=a(1+costheta) at theta=-pi//2