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If `3(a+2c)=4(b+3d),` then the equation `a x^3+b x^2+c x+d=0` will have no real solution at least one real root in `(-1,0)` at least one real root in `(0,1)` none of these

A

atleast one root in `(-1,0)`

B

atleast one root in (0, 1)

C

no root in `(-1, 1)`

D

no root in (0, 2)

Text Solution

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The correct Answer is:
B
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