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To find the point of contact P (x1, y1) ...

To find the point of contact `P (x_1, y_1)` of a tangent to the graph of `y = f(x)` passing through origin O, we equate the slope of tangent to `y = f(x)` at P to the slope of OP. Hence we solve the equation `f' (x) = f(x_1)/x_1` to get `x_1` and `y_1`.Now answer the following questions (7 -9): The equation `|lnmx|= px` where m is a positive constant has a single root for

A

`p(m)/(e)`

B

`p=(e)/(m)`

C

`0lt ple(e)/(m)`

D

`0lt p le(m)/(e)`

Text Solution

Verified by Experts

The correct Answer is:
A
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