A normal is drawn at a point `P(x , y)` of a curve. It meets the x-axis at `Qdot` If `P Q` has constant length `k ,` then show that the differential equation describing such curves is `y(dy)/(dx)=+-sqrt(k^2-y^2)` . Find the equation of such a curve passing through `(0, k)dot`

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Find coordinates of q also find equation of curve

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:The differential equation describing such a curve is (A) y dy/dx=+-sqrt(k^2-x^2) (B) x dy/dx=+-sqrt(k^2-x^2) (C) y dy/dx=+-sqrt(k^2-y^2) (D) x dy/dx=+-sqrt(k^2-y^2)

For the differential equation x y(dy)/(dx)=(x+2)(y+2) , find the solution curve passing through the point (1, 1) .

For the differential equation x y(dy)/(dx)=(x+2)(y+2) , find the solution curve passing through the point (1, -1) .

If slope of the tangent at the point (x, y) on the curve is (y-1)/(x^(2)+x) , then the equation of the curve passing through M(1, 0) is :

A normal is drawn at a point P(x , y) of a curve. It meets the x-axis and the y-axis in point A AND B , respectively, such that 1/(O A)+1/(O B) =1, where O is the origin. Find the equation of such a curve passing through (5, 4)

Find the equation of the normal to curve x^2=4y which passes through the point (1, 2).

Find the equation of the normal to curve x^2=4y which passes through the point (1, 2).

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:If the curve passes through the point (0,k) , then its equation is (A) x^2-y^2=k^2 (B) x^2+y^2=k^2 (C) x^2-y^2=2k^2 (D) x^2+y^2=2k^2

Tangent to a curve intercepts the y-axis at a point P .A line perpendicular to this tangent through P passes through another point (1,0). The differential equation of the curve is