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Let a,b,c be the sides of triangle whose...

Let a,b,c be the sides of triangle whose perimeter is P and area is A, then

A

`p^(3)le 27 (b+c-a) (c+a-b) (a+b-c)`

B

`p^(2)le 3 (a^(2)+b^(2) +c^(2))`

C

`a^(2)+ b^(2) +c^(2) ge 4 sqrt3A`

D

`p^(4) le 25 ltA`

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The correct Answer is:
To solve the problem, we need to analyze the relationships between the sides \( a, b, c \) of a triangle, its perimeter \( P \), and its area \( A \). We will derive inequalities that are true for any triangle based on these parameters. ### Step-by-Step Solution: 1. **Understanding the Perimeter and Area**: - The perimeter \( P \) of the triangle is given by: \[ P = a + b + c \] - The area \( A \) can be calculated using Heron's formula: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \] where \( s = \frac{P}{2} = \frac{a+b+c}{2} \). 2. **Using the Triangle Inequalities**: - For any triangle, the following inequalities must hold: \[ a + b > c, \quad b + c > a, \quad c + a > b \] - This implies that the differences \( b+c-a \), \( c+a-b \), and \( a+b-c \) are all positive. 3. **Applying the Arithmetic Mean-Geometric Mean (AM-GM) Inequality**: - By applying the AM-GM inequality to the three positive terms \( b+c-a \), \( c+a-b \), and \( a+b-c \), we have: \[ \frac{(b+c-a) + (c+a-b) + (a+b-c)}{3} \geq \sqrt[3]{(b+c-a)(c+a-b)(a+b-c)} \] - Simplifying the left-hand side gives: \[ \frac{P}{3} \geq \sqrt[3]{(b+c-a)(c+a-b)(a+b-c)} \] 4. **Cubing Both Sides**: - Cubing both sides of the inequality results in: \[ \left(\frac{P}{3}\right)^3 \geq (b+c-a)(c+a-b)(a+b-c) \] - This can be rewritten as: \[ \frac{P^3}{27} \geq (b+c-a)(c+a-b)(a+b-c) \] 5. **Finding the Area in Terms of the Sides**: - The area \( A \) can also be expressed in terms of the sides using the formula: \[ A^2 = s(s-a)(s-b)(s-c) \] - This can be used to derive inequalities relating \( A \) and \( P \). 6. **Final Inequality**: - From the previous steps, we can derive that: \[ P^4 \leq 256A \] - This means that for any triangle, the fourth power of the perimeter is less than or equal to a constant multiplied by the area. ### Conclusion: The inequalities derived from the properties of triangles provide valuable insights into the relationships between the sides, perimeter, and area. The inequalities we have established are fundamental in triangle geometry.
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