If 7 divides `32^(32^(32))`, then find the remainder

Explanation

To solve the problem of finding the remainder when \( 32^{32^{32}} \) is divided by 7, we can follow these steps:

### Step 1: Simplify the base
We start by rewriting \( 32 \) in terms of \( 7 \):
\[ 32 \equiv 4 \mod 7 \]
This means we can replace \( 32 \) with \( 4 \) in our expression:
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