If `(1+x)^n=c_0+c_1x+c_2x^2+...+c_nx^n` then the value of `c_0+3c_1+5c_2+....+(2n+1)c_n` is-

Explanation

To solve the problem, we need to find the value of \( c_0 + 3c_1 + 5c_2 + \ldots + (2n+1)c_n \) given the expansion of \( (1+x)^n = c_0 + c_1 x + c_2 x^2 + \ldots + c_n x^n \).

### Step-by-Step Solution:

1. **Understand the Binomial Expansion**:
The binomial expansion of \( (1+x)^n \) is given by:
\[
(1+x)^n = \sum_{k=0}^{n} c_k x^k
...