Find a point P on the line `3x+2y+10=0` such that `|PA - PB| `is minimum where A is (4,2) and B is (2,4)

The co-ordinates of a point P on the line 2x - y + 5 = 0 such that |PA - PB| is maximum where A is (4,-2) and B is (2,-4) will be

The coordinates of the point P on the line 2x + 3y +1=0 such that |PA-PB| is maximum where A is (2,0) and B is (0,2) is

STATEMENT-1: The point P(-22,28) lies on the line 3x+2y+10=0 such that for the points A(4,2)and B(2,4),|PA-PB| is maximum. STATEMENT-2: A point P on ax+by+c=0 such that |PA-PB| maximum is determined by the point of intersection of the line AB and Ax+by+c=0.

Find the point P on the circle x^2+y^2 -4x-6y+9=0 such that (i) /_POX is minimum (ii) OP is maximum, where O is the origin and OX is the x-axis.

Statement I Let A-= (0,1) and B -= (2,0) and P be a point on the line 4x+3y+9=0 then the co - ordinates of P such that |PA -PB| is maximum is (-12/5,17/5) Statement II |PA - PB | le |AB|

P is a point lying on line y = x then maximum value of |PA - PB| , (where A-=(1, 3), B-=(5, 2) ) is

If A(-3,4) ,B(5,6),then find point P on x-axis such that PA+PB is Minimum.

Let A(1, 2) and B(-2,-4) be two fixed points. A variable point P.is chosen on the straight line y=x such that perimeter of DeltaPAB is minimum. Find coordinates of P.

P(1, -2) is a point on the line segment A(3, -6) and B(x, y) such that AP:PB is equal to 2:3 . Find the coordinates of B.

Find the locus of the point P such that PA^2+PB^2=2c^2 :where A(a,0),B(-a,0) and 0 lt |a| lt |c|.