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The straight lines x+2y-9=0,3x+5y-5=0 , ...

The straight lines `x+2y-9=0,3x+5y-5=0` , and `a x+b y-1=0` are concurrent, if the straight line `35 x-22 y+1=0` passes through the point `(a , b)` (b) `(b ,a)` `(-a ,-b)` (d) none of these

A

`(a,b)`

B

`(b,a)`

C

`(a,-b)`

D

`(-a,b)`

Text Solution

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The correct Answer is:
To determine the point \((a, b)\) such that the lines \(x + 2y - 9 = 0\), \(3x + 5y - 5 = 0\), and \(ax + by - 1 = 0\) are concurrent, and the line \(35x - 22y + 1 = 0\) passes through this point, we can follow these steps: ### Step 1: Set up the condition for concurrency The three lines are concurrent if the determinant of their coefficients is zero. Therefore, we can write the determinant as follows: \[ \begin{vmatrix} 1 & 2 & -9 \\ 3 & 5 & -5 \\ a & b & -1 \end{vmatrix} = 0 \] ### Step 2: Calculate the determinant Calculating the determinant, we have: \[ 1 \cdot (5 \cdot (-1) - (-5) \cdot b) - 2 \cdot (3 \cdot (-1) - (-5) \cdot a) - 9 \cdot (3b - 5a) = 0 \] This simplifies to: \[ 1 \cdot (-5 + 5b) - 2 \cdot (-3 + 5a) - 9 \cdot (3b - 5a) = 0 \] ### Step 3: Expand and simplify the equation Expanding this, we get: \[ -5 + 5b + 6 - 10a - 27b + 45a = 0 \] Combining like terms results in: \[ (35a - 22b + 1) = 0 \] ### Step 4: Set up the equation with the line \(35x - 22y + 1 = 0\) Since the line \(35x - 22y + 1 = 0\) passes through the point \((a, b)\), we can substitute \(x = a\) and \(y = b\): \[ 35a - 22b + 1 = 0 \] ### Step 5: Solve for \(a\) and \(b\) From the equation \(35a - 22b + 1 = 0\), we can express \(b\) in terms of \(a\): \[ 22b = 35a + 1 \implies b = \frac{35a + 1}{22} \] ### Step 6: Identify the point \((a, b)\) Now we have \(b\) expressed in terms of \(a\). Thus, the point \((a, b)\) can be represented as: \[ \left(a, \frac{35a + 1}{22}\right) \] ### Step 7: Check the options We need to check which of the given options corresponds to this point. The options provided were: (a) \((a, b)\) (b) \((b, a)\) (c) \((-a, -b)\) (d) none of these Since we have \(b = \frac{35a + 1}{22}\), option (a) \((a, b)\) is indeed the correct representation of the point. ### Conclusion The correct answer is (a) \((a, b)\). ---
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