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If the eccentricities of the two ellip...

If the eccentricities of the two ellipse `(x^(2))/(169)+(y^(2))/(25)=1 and (x^(2))/(a^(2))+(y^(2))/(b^(2))=1` and equal , then the value `(a)/(b) ` , is

A

`5/13`

B

`6/13`

C

`13/5`

D

`13/6`

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The correct Answer is:
To solve the problem, we need to find the value of \( \frac{a}{b} \) given that the eccentricities of two ellipses are equal. Let's break it down step by step. ### Step 1: Identify the eccentricity of the first ellipse The first ellipse is given by the equation: \[ \frac{x^2}{169} + \frac{y^2}{25} = 1 \] Here, \( a^2 = 169 \) and \( b^2 = 25 \). The eccentricity \( e_1 \) of an ellipse is given by the formula: \[ e = \sqrt{1 - \frac{b^2}{a^2}} \] Substituting the values: \[ e_1 = \sqrt{1 - \frac{25}{169}} \] ### Step 2: Simplify the expression for \( e_1 \) Calculating \( \frac{25}{169} \): \[ e_1 = \sqrt{1 - \frac{25}{169}} = \sqrt{\frac{169 - 25}{169}} = \sqrt{\frac{144}{169}} = \frac{12}{13} \] ### Step 3: Identify the eccentricity of the second ellipse The second ellipse is given by the equation: \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] The eccentricity \( e_2 \) of this ellipse is given by: \[ e_2 = \sqrt{1 - \frac{b^2}{a^2}} \] ### Step 4: Set the eccentricities equal According to the problem, the eccentricities of the two ellipses are equal: \[ e_1 = e_2 \] Thus, we have: \[ \frac{12}{13} = \sqrt{1 - \frac{b^2}{a^2}} \] ### Step 5: Square both sides to eliminate the square root Squaring both sides gives: \[ \left(\frac{12}{13}\right)^2 = 1 - \frac{b^2}{a^2} \] Calculating \( \left(\frac{12}{13}\right)^2 \): \[ \frac{144}{169} = 1 - \frac{b^2}{a^2} \] ### Step 6: Rearranging the equation Rearranging the equation gives: \[ \frac{b^2}{a^2} = 1 - \frac{144}{169} = \frac{169 - 144}{169} = \frac{25}{169} \] ### Step 7: Take the square root Taking the square root of both sides: \[ \frac{b}{a} = \frac{5}{13} \] ### Step 8: Find \( \frac{a}{b} \) To find \( \frac{a}{b} \), we take the reciprocal: \[ \frac{a}{b} = \frac{13}{5} \] ### Final Answer Thus, the value of \( \frac{a}{b} \) is: \[ \frac{a}{b} = \frac{13}{5} \]
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ARIHANT MATHS ENGLISH-ELLIPSE-Exercise For Session 1
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  8. If the eccentricities of the two ellipse (x^(2))/(169)+(y^(2))/(25)=...

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  9. The ratio of the area of triangle inscribed in ellipse (x^2)/(a^2)+...

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  10. If PSQ is a focal chord of the ellipse 16x^(2)+25y^(2)=400 such that S...

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  11. Let P be a variable point on the ellipse x^(2)/25 + y^(2)/16 = 1 with ...

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  12. S1a n dS2 are the foci of an ellipse of major axis of length 10 units,...

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  13. Find the latus rectum, eccentricity, coordinates of the foci and the l...

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  14. The distance between the foci of an ellipse is 10 and its latus rectum...

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  15. Find the equation of the ellipse whose axes are parallel to the coo...

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  16. Find the equation of the ellipse whose foci are (2,3),(-2,3) and whose...

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