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The locus of extremities of the latus re...

The locus of extremities of the latus rectum of the family of ellipse `b^2x^2+a^2y^2=a^2b^2` is

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To find the locus of the extremities of the latus rectum of the family of ellipses given by the equation \( b^2x^2 + a^2y^2 = a^2b^2 \), we will follow these steps: ### Step 1: Rewrite the equation of the ellipse The given equation of the ellipse is: \[ b^2x^2 + a^2y^2 = a^2b^2 \] We can divide the entire equation by \( a^2 \) to simplify it: \[ \frac{b^2}{a^2}x^2 + y^2 = b^2 \] This can be rewritten as: \[ \frac{x^2}{\frac{a^2}{b^2}} + \frac{y^2}{b^2} = 1 \] This represents an ellipse centered at the origin with semi-major axis \( b \) and semi-minor axis \( \frac{a}{b} \). ### Step 2: Identify the coordinates of the extremities of the latus rectum The latus rectum of an ellipse is a line segment perpendicular to the major axis that passes through a focus. The coordinates of the extremities of the latus rectum for an ellipse can be given by: \[ \left( ae, \frac{b^2}{a} \right) \quad \text{and} \quad \left( ae, -\frac{b^2}{a} \right) \] where \( e \) is the eccentricity of the ellipse, defined as: \[ e = \sqrt{1 - \frac{b^2}{a^2}} \] ### Step 3: Substitute the value of eccentricity Substituting \( e \) into the coordinates: \[ H = ae = a\sqrt{1 - \frac{b^2}{a^2}} = a\sqrt{\frac{a^2 - b^2}{a^2}} = \sqrt{a^2 - b^2} \] Thus, the coordinates of the extremities of the latus rectum become: \[ \left( \sqrt{a^2 - b^2}, \frac{b^2}{a} \right) \quad \text{and} \quad \left( \sqrt{a^2 - b^2}, -\frac{b^2}{a} \right) \] ### Step 4: Find the locus Let \( H = \sqrt{a^2 - b^2} \) and \( K = \frac{b^2}{a} \). We can express \( b^2 \) in terms of \( H \): \[ b^2 = a^2 - H^2 \] Substituting this into the expression for \( K \): \[ K = \frac{a^2 - H^2}{a} \] This gives us: \[ K = a - \frac{H^2}{a} \] Rearranging gives: \[ H^2 + aK - a^2 = 0 \] ### Step 5: Final equation of the locus Replacing \( H \) with \( x \) and \( K \) with \( y \): \[ x^2 + ay - a^2 = 0 \] This is the equation of the locus of the extremities of the latus rectum.
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ARIHANT MATHS ENGLISH-ELLIPSE-Exercise For Session 1
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  8. If the eccentricities of the two ellipse (x^(2))/(169)+(y^(2))/(25)=...

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  9. The ratio of the area of triangle inscribed in ellipse (x^2)/(a^2)+...

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  10. If PSQ is a focal chord of the ellipse 16x^(2)+25y^(2)=400 such that S...

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  11. Let P be a variable point on the ellipse x^(2)/25 + y^(2)/16 = 1 with ...

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  13. Find the latus rectum, eccentricity, coordinates of the foci and the l...

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  14. The distance between the foci of an ellipse is 10 and its latus rectum...

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  15. Find the equation of the ellipse whose axes are parallel to the coo...

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  16. Find the equation of the ellipse whose foci are (2,3),(-2,3) and whose...

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