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The eccentric angle of one end of a diam...

The eccentric angle of one end of a diameter of `x^(2)+3y^(2)=3` is `pi/6`, then the eccentric angle of the other end will be

A

`(5pi)/6`

B

`-5pi/6`

C

`-2pi/3`

D

`2pi/3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the eccentric angle of the other end of the diameter of the ellipse given by the equation \(x^2 + 3y^2 = 3\), where one end of the diameter has an eccentric angle of \(\frac{\pi}{6}\). ### Step-by-Step Solution: 1. **Rewrite the Equation of the Ellipse**: The given equation is: \[ x^2 + 3y^2 = 3 \] To convert it into standard form, divide the entire equation by 3: \[ \frac{x^2}{3} + \frac{y^2}{1} = 1 \] This shows that the semi-major axis \(a = \sqrt{3}\) and the semi-minor axis \(b = 1\). **Hint**: To convert the equation of an ellipse into standard form, divide by the constant on the right side. 2. **Identify the Axes**: From the standard form, we can see that the major axis is along the x-axis and the minor axis is along the y-axis. **Hint**: Remember that the semi-major axis is the larger value when comparing \(a\) and \(b\). 3. **Understanding Eccentric Angles**: The eccentric angle \(\theta\) is the angle formed with the positive x-axis. If one end of the diameter has an eccentric angle of \(\frac{\pi}{6}\), we need to find the angle of the other end of the diameter. **Hint**: The eccentric angle is measured from the positive x-axis in the anticlockwise direction. 4. **Using the Linear Angle Property**: The sum of angles on a straight line is \(\pi\) radians (or 180 degrees). If one end of the diameter makes an angle of \(\frac{\pi}{6}\) with the x-axis, the angle of the other end can be found using: \[ \theta + \text{other angle} = \pi \] Let the other angle be \(\theta'\): \[ \frac{\pi}{6} + \theta' = \pi \] Rearranging gives: \[ \theta' = \pi - \frac{\pi}{6} \] **Hint**: To find the other angle on a straight line, subtract the known angle from \(\pi\). 5. **Calculating the Other Angle**: To find \(\theta'\): \[ \theta' = \frac{6\pi}{6} - \frac{\pi}{6} = \frac{5\pi}{6} \] **Hint**: Make sure to convert all terms to a common denominator when performing subtraction. 6. **Considering the Direction**: Since the diameter is measured in the anticlockwise direction, we denote this angle as: \[ -\frac{5\pi}{6} \] This negative sign indicates the direction of measurement. **Hint**: When measuring angles in a coordinate system, the direction (clockwise or anticlockwise) can affect the sign of the angle. ### Final Answer: The eccentric angle of the other end of the diameter is: \[ -\frac{5\pi}{6} \]
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