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An ellipse whose distance between foci ...

An ellipse whose distance between foci `S and S'` is 4 units is inscribed in the `DeltaABC` touching thesides `AB, AC and BC at P, Q and R`. If centre of ellipse is at origin and major axis along x-axis `SP + S'P = 6`, then

A

`9x^(2)+5y^(2)=45`

B

`4x^(2)+9y^(2)=46`

C

`5x^(2)+9y^(2)=45`

D

`9x^(2)+4y^(2)=36`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the equation of the ellipse inscribed in triangle ABC, given the conditions. Let's break it down step by step. ### Step 1: Understanding the Given Information - The distance between the foci \( S \) and \( S' \) is 4 units. - The center of the ellipse is at the origin (0, 0). - The major axis is along the x-axis. - The sum of the distances from the foci to a point \( P \) on the ellipse is given as \( SP + S'P = 6 \). ### Step 2: Relating the Distance Between Foci to the Major Axis The distance between the foci \( S \) and \( S' \) is given by \( 2c \), where \( c \) is the distance from the center to each focus. Since the distance is 4 units, we have: \[ 2c = 4 \implies c = 2 \] ### Step 3: Using the Relationship Between Major Axis and Foci For an ellipse, the relationship between the semi-major axis \( a \), semi-minor axis \( b \), and the distance \( c \) is given by: \[ c^2 = a^2 - b^2 \] We also know from the property of ellipses that: \[ SP + S'P = 2a \] Given \( SP + S'P = 6 \), we can equate this to find \( a \): \[ 2a = 6 \implies a = 3 \] ### Step 4: Finding the Value of \( b \) Now we have \( a = 3 \) and \( c = 2 \). We can use the relationship \( c^2 = a^2 - b^2 \): \[ c^2 = 2^2 = 4 \] \[ a^2 = 3^2 = 9 \] Substituting these values into the equation: \[ 4 = 9 - b^2 \implies b^2 = 9 - 4 = 5 \] ### Step 5: Writing the Equation of the Ellipse The standard form of the equation of an ellipse centered at the origin with the major axis along the x-axis is given by: \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Substituting the values of \( a^2 \) and \( b^2 \): \[ \frac{x^2}{9} + \frac{y^2}{5} = 1 \] ### Step 6: Rearranging the Equation To express this in a more standard form, we can multiply through by 45 (the least common multiple of the denominators): \[ 5x^2 + 9y^2 = 45 \] ### Final Answer The equation of the ellipse is: \[ 5x^2 + 9y^2 = 45 \]
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