Home
Class 12
MATHS
The circle x^2+y^2-8x = 0 and hyperbola ...

The circle `x^2+y^2-8x = 0` and hyperbola `x^2 /9 - y^2 /4=1` intersect at the points A and B. Then the equation of the circle with AB as its diameter is

A

`x^(2)+y^(2)-12x+24=0`

B

`x^(2)+y^(2)+12x+24=0`

C

`x^(2)+y^(2)+24x-12=0`

D

`x^(2)+y^(2)-24x-12=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    ARIHANT MATHS ENGLISH|Exercise Hyperbola Exercise 11 : Questions Asked in Previous 13 Years Exams|3 Videos

  • HYPERBOLA

    ARIHANT MATHS ENGLISH|Exercise Hyperbola Exercise 10 : Subjective Type Questions|3 Videos

  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

  • INDEFINITE INTEGRAL

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|8 Videos

Similar Questions

Explore conceptually related problems

The circles x^2 + y^2 - 4x - 81 =0 and x^2 + y^2 + 24x - 81=0 intersect each other at A and B . The equation of the circle with AB as the diameter is : (A) x^2 + y^2 = 81 (B) x^2 + y^2 = 9 (C) x^2 + y^2 = 16 (D) x^2 + y^2 = 1

The circle x^2+y^2-8x=0 and hyperbola x^2/9-y^2/4=1 I intersect at the points A and B. Equation of a common tangent with positive slope to the circle as well as to the hyperbola is

Let the line segment joining the centres of the circles x^(2)-2x+y^(2)=0 and x^(2)+y^(2)+4x+8y+16=0 intersect the circles at P and Q respectively. Then the equation of the circle with PQ as its diameter is

The ellipse 4x^2+9y^2=36 and the hyperbola a^2x^2-y^2=4 intersect at right angles. Then the equation of the circle through the points of intersection of two conics is

The ellipse 4x^2+9y^2=36 and the hyperbola a^2x^2-y^2=4 intersect at right angles. Then the equation of the circle through the points of intersection of two conics is (a) x^2+y^2=5 (b) sqrt(5)(x^2+y^2)-3x-4y=0 (c) sqrt(5)(x^2+y^2)+3x+4y=0 (d) x^2+y^2=25

The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A and B , Then the equation of the circle on AB as diameter is

If the straight line represented by x cos alpha + y sin alpha = p intersect the circle x^2+y^2=a^2 at the points A and B , then show that the equation of the circle with AB as diameter is (x^2+y^2-a^2)-2p(xcos alpha+y sin alpha-p)=0

If the straight line 2x+3y=1 intersects the circle x^2+y^2=4 at the points A and B then find the equation of the circle having AB as diameter.

The line 2x -y +6= 0 meets the circle x^2+y^2 -2y-9 =0 at A and B. Find the equation of the circle on AB as diameter.

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.