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A function `f` is defined by `f(x)=int_(0)^(pi)cos t cos (x-t)dt, 0 lexle2pi` then the minimum value of `f(x)` is

A

f(x) is continuos but not differentiable in `(0,2pi)`

B

Maximum value of f is `pi`

C

There exists atleast one `c in (0,2pi)if f'(c)=0`

D

Minimum value of f is `-(pi)/(2)`

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The correct Answer is:
A, B
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