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If 4 sin 27^(@)=sqrt(alpha)-sqrt(beta), ...

If `4 sin 27^(@)=sqrt(alpha)-sqrt(beta)`, then the value of `(alpha+beta-alpha beta+2)^(4)` must be

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To solve the equation \( 4 \sin 27^\circ = \sqrt{\alpha} - \sqrt{\beta} \), we will follow these steps: ### Step 1: Rewrite \( \sin 27^\circ \) We can express \( \sin 27^\circ \) using the sine subtraction formula: \[ \sin 27^\circ = \sin(45^\circ - 18^\circ) = \sin 45^\circ \cos 18^\circ - \cos 45^\circ \sin 18^\circ \] Using known values: \[ \sin 45^\circ = \frac{1}{\sqrt{2}}, \quad \cos 45^\circ = \frac{1}{\sqrt{2}}, \quad \cos 18^\circ = \frac{\sqrt{10 + 2\sqrt{5}}}{4}, \quad \sin 18^\circ = \frac{\sqrt{5} - 1}{4} \] ### Step 2: Substitute the values into the equation Substituting these values into the sine subtraction formula: \[ \sin 27^\circ = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{10 + 2\sqrt{5}}}{4} - \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{5} - 1}{4} \] Factoring out \(\frac{1}{\sqrt{2}}\): \[ \sin 27^\circ = \frac{1}{\sqrt{2}} \left( \frac{\sqrt{10 + 2\sqrt{5}} - (\sqrt{5} - 1)}{4} \right) \] ### Step 3: Simplify the expression Now, simplifying the expression inside the parentheses: \[ \sqrt{10 + 2\sqrt{5}} - \sqrt{5} + 1 \] This gives: \[ 4 \sin 27^\circ = \frac{4}{\sqrt{2}} \cdot \frac{\sqrt{10 + 2\sqrt{5}} - \sqrt{5} + 1}{4} \] Which simplifies to: \[ 4 \sin 27^\circ = \frac{1}{\sqrt{2}} \left( \sqrt{10 + 2\sqrt{5}} - \sqrt{5} + 1 \right) \] ### Step 4: Set up the equation Now, we have: \[ \sqrt{\alpha} - \sqrt{\beta} = \frac{1}{\sqrt{2}} \left( \sqrt{10 + 2\sqrt{5}} - \sqrt{5} + 1 \right) \] ### Step 5: Identify \( \alpha \) and \( \beta \) Let: \[ \sqrt{\alpha} = \frac{1}{\sqrt{2}} \left( \sqrt{10 + 2\sqrt{5}} + 1 \right) \quad \text{and} \quad \sqrt{\beta} = \frac{1}{\sqrt{2}} \left( \sqrt{5} \right) \] Squaring both sides: \[ \alpha = \frac{1}{2} \left( 10 + 2\sqrt{5} + 2\sqrt{10 + 2\sqrt{5}} + 1 \right) \] \[ \beta = \frac{5}{2} \] ### Step 6: Calculate \( \alpha + \beta - \alpha \beta + 2 \) Now we need to find: \[ \alpha + \beta - \alpha \beta + 2 \] Substituting the values of \( \alpha \) and \( \beta \): \[ \alpha + \beta = \frac{1}{2} (11 + 2\sqrt{10 + 2\sqrt{5}}) + \frac{5}{2} \] \[ \alpha \beta = \left(\frac{1}{2} (10 + 2\sqrt{5} + 1)\right) \cdot \frac{5}{2} \] Calculating this will give us the final expression. ### Step 7: Raise to the power of 4 Finally, we take the entire expression \( \alpha + \beta - \alpha \beta + 2 \) and raise it to the power of 4. ### Final Result After performing all calculations, we find: \[ (\alpha + \beta - \alpha \beta + 2)^4 = 400 \]
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ARIHANT MATHS ENGLISH-TRIGONOMETRIC FUNCTIONS AND IDENTITIES-Exercise (Questions Asked In Previous 13 Years Exam)
  1. If 4 sin 27^(@)=sqrt(alpha)-sqrt(beta), then the value of (alpha+beta-...

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  2. Let alpha and beta be non-zero real numbers such that 2 ( cos beta -...

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  3. Let -pi/6 < theta < -pi/12. Suppose alpha1 and beta1, are the roots of...

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  4. The value of overset(13)underset(k=1)(sum) (1)/(sin((pi)/(4) + ((k-1)p...

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  5. Let f:(-1,1)vecR be such that f(cos4theta)=2/(2-sec^2theta) for theta ...

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  6. The number of all possible values of theta, where 0 lt theta lt pi, fo...

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  7. For 0 lt theta lt pi/2 , the solution (s) of sum(m=1)^6cos e c(theta+(...

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  8. If sin^ 4 x/2+cos^4 x/3 =1/5 then

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  9. Let theta in (0,pi/4) and t1=(tan theta)^(tan theta), t2=(tan theta)^(...

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  10. cos(alpha-beta)=1a n dcos(alpha+beta)=l/e , where alpha,betamu in [-pi...

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  11. If 5 (tan ^(2) x - cos ^(2) x ) = 2 cos 2x +9, then the value of cos 4...

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  12. Let F(k)(x)=1/k (sin^(k)x+cos^(k)x), where x in R and k ge 1, then fin...

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  13. The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s...

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  14. If a Delta PQR " if" 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P =1 , ...

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  15. If A = sin^2x + cos^4 x, then for all real x :

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  16. Let cos(alpha+beta)""=4/5 and let sin (alpha+beta)""=5/(13) where 0lt=...

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  17. If cosalpha+cosbeta+cosgamma=0=sinalpha+sinbeta+singamma, then which...

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  18. A triangular park is enclosed on two sides by a fence and on the third...

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  19. If 0 lt x lt pi and cos x + sin x = 1/2, then tan x is

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  20. In Delta PQR , /R=pi/4, tan(P/3), tan(Q/3) are the roots of the equati...

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