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Let hata and hatb be two unit vectors. I...

Let `hata and hatb` be two unit vectors. If the vectors `vecc=hata+2hatb and vecd=5hata-4hatb` are perpendicular to each other then the angle between `hata and hatb` is (A) `pi/2` (B) `pi/3` (C) `pi/4` (D) `pi/6`

A

`pi/6`

B

`pi/2`

C

`pi/3`

D

`pi/4`

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The correct Answer is:
To solve the problem, we need to find the angle between the unit vectors \(\hat{a}\) and \(\hat{b}\) given that the vectors \(\vec{c} = \hat{a} + 2\hat{b}\) and \(\vec{d} = 5\hat{a} - 4\hat{b}\) are perpendicular to each other. ### Step-by-step Solution: 1. **Understanding Perpendicular Vectors**: Since \(\vec{c}\) and \(\vec{d}\) are perpendicular, their dot product must equal zero: \[ \vec{c} \cdot \vec{d} = 0 \] 2. **Substituting the Vectors**: Substitute \(\vec{c}\) and \(\vec{d}\): \[ (\hat{a} + 2\hat{b}) \cdot (5\hat{a} - 4\hat{b}) = 0 \] 3. **Expanding the Dot Product**: Use the distributive property of the dot product: \[ \hat{a} \cdot (5\hat{a}) + \hat{a} \cdot (-4\hat{b}) + 2\hat{b} \cdot (5\hat{a}) + 2\hat{b} \cdot (-4\hat{b}) = 0 \] This simplifies to: \[ 5(\hat{a} \cdot \hat{a}) - 4(\hat{a} \cdot \hat{b}) + 10(\hat{b} \cdot \hat{a}) - 8(\hat{b} \cdot \hat{b}) = 0 \] 4. **Using Properties of Unit Vectors**: Since \(\hat{a}\) and \(\hat{b}\) are unit vectors: \[ \hat{a} \cdot \hat{a} = 1 \quad \text{and} \quad \hat{b} \cdot \hat{b} = 1 \] Thus, we can substitute: \[ 5(1) - 4(\hat{a} \cdot \hat{b}) + 10(\hat{a} \cdot \hat{b}) - 8(1) = 0 \] 5. **Simplifying the Equation**: Combine like terms: \[ 5 - 8 + (10 - 4)(\hat{a} \cdot \hat{b}) = 0 \] Which simplifies to: \[ -3 + 6(\hat{a} \cdot \hat{b}) = 0 \] 6. **Solving for the Dot Product**: Rearranging gives: \[ 6(\hat{a} \cdot \hat{b}) = 3 \] Thus: \[ \hat{a} \cdot \hat{b} = \frac{1}{2} \] 7. **Finding the Angle**: Recall that the dot product of two vectors is given by: \[ \hat{a} \cdot \hat{b} = |\hat{a}| |\hat{b}| \cos \theta \] Since both are unit vectors: \[ \hat{a} \cdot \hat{b} = 1 \cdot 1 \cdot \cos \theta = \cos \theta \] Therefore: \[ \cos \theta = \frac{1}{2} \] 8. **Determining the Angle**: The angle \(\theta\) that satisfies \(\cos \theta = \frac{1}{2}\) is: \[ \theta = \frac{\pi}{3} \] ### Final Answer: The angle between \(\hat{a}\) and \(\hat{b}\) is \(\frac{\pi}{3}\).
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ARIHANT MATHS ENGLISH-PRODUCT OF VECTORS-Exercise (Questions Asked In Previous 13 Years Exam)
  1. Let a= 2hat(i) -2hat(k) , b=hat(i) +hat(j) and c be a vectors suc...

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  2. If [axxb bxxc c xxa]=lambda[abc]^(2), then lambda is equal to

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  3. Let hata and hatb be two unit vectors. If the vectors vecc=hata+2hatb ...

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  4. Let ABCD be a parallelogram such that vec A B= vec q , vec A D= vec p...

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  5. veca =1/sqrt(10)(3hati + hatk) and vecb =1/7(2hati +3hatj-6hatk), then...

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  6. The vectors vec a and vec b are not perpendicular and vec c and v...

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  7. If the vectors ahat(i)+hat(j)+hat(k), hat(i)+bhat(j)+hat(k), hat(i)+ha...

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  8. Let veca =hatj-hatk and vecc =hati-hatj-hatk. Then the vector b satisf...

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  9. If the vectors veca=hati-hatj+2hatk.vecb=2hati+4hatj+hatk and veccc=la...

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  10. If vecu, vecv, vecw are non -coplanar vectors and p,q, are real numbe...

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  11. The vector vec a=""alpha hat i+2 hat j+""beta hat k lies in the pl...

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  12. If vecu and vecv are unit vectors and theta is the acute angle bet...

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  13. Let bar a= hat i+ hat j+ hat k ,""b= hat i- hat j+2 hat k and bar...

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  14. If (vecaxxvecb)xxvecc=vecaxx(vecbxxvecc), Where veca, vecb and vecc a...

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  15. The values of a for which the points A, B, and C with position vectors...

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  16. The distance between the line r=2hat(i)-2hat(j)+3hat(k)+lambda(hat(i)-...

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  17. If veca is any vector, then (vec a xx vec i)^2+(vec a xx vecj)^2+(ve...

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  18. If veca,vecb,vecc are non-coplanar vectors and lambda is a real number...

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  19. If vec(a)=hat(i)-hat(k), vec(b)=xhat(i)+hat(j)+(1-x)hat(k) vec(c)=yh...

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  20. Let vec u , vec va n d vec w be such that | vec u|=1,| vec v|=2a n d|...

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