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Mr. Richard has a recurring deposite account in a bank for 3 years at 7.5% p.a. simple interest. If he gets Rs 8325 as interest at the time of maturity, find the maturity value.

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To solve the problem step by step, we will follow the given information and apply the relevant formulas. ### Step 1: Understand the Problem Mr. Richard has a recurring deposit account for 3 years at a simple interest rate of 7.5% per annum. He receives Rs. 8325 as interest at maturity, and we need to find the maturity value. ### Step 2: Identify the Variables - Interest (I) = Rs. 8325 - Rate of interest (R) = 7.5% per annum - Time (T) = 3 years - Total number of months (N) = 3 years × 12 months/year = 36 months ### Step 3: Use the Formula for Simple Interest The formula for simple interest is: \[ I = P \times R \times T \] Where: - \( P \) is the principal amount (total deposits) - \( R \) is the rate of interest per annum - \( T \) is the time in years ### Step 4: Calculate the Monthly Installment (P) For a recurring deposit, the total principal deposited can be calculated using the formula: \[ P = \frac{I \times 100 \times 12}{(N + 1) \times N \times R} \] Substituting the known values: - \( I = 8325 \) - \( N = 36 \) - \( R = 7.5 \) Now substituting these values into the formula: \[ P = \frac{8325 \times 100 \times 12}{(36 + 1) \times 36 \times 7.5} \] ### Step 5: Simplify the Calculation Calculating the denominator: - \( N + 1 = 37 \) - \( N = 36 \) - \( R = 7.5 \) Now calculating: \[ P = \frac{8325 \times 100 \times 12}{37 \times 36 \times 7.5} \] Calculating the denominator: \[ 37 \times 36 = 1332 \] \[ 1332 \times 7.5 = 9990 \] Now substituting back: \[ P = \frac{8325 \times 1200}{9990} \] Calculating the numerator: \[ 8325 \times 1200 = 9990000 \] Now dividing: \[ P = \frac{9990000}{9990} = 1000 \] ### Step 6: Calculate the Maturity Value The maturity value (MV) is given by: \[ MV = (N \times P) + I \] Where: - \( N = 36 \) - \( P = 2000 \) - \( I = 8325 \) Substituting the values: \[ MV = (36 \times 2000) + 8325 \] \[ MV = 72000 + 8325 = 80325 \] ### Final Answer The maturity value is Rs. 80325. ---
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