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In trapezium ABCD, as shown, AB||DC, AD ...

In trapezium ABCD, as shown, AB||DC, AD = DC = BC = 20 cm and `angle A = 60^(@)` Find :
(i) length of AB
(ii) distance between AB and DC

Text Solution

Verified by Experts

The correct Answer is:
(i) AB = 40 cm
(ii) AB = CD is 17.32 cm
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