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Find the number of terms in the expansio...

Find the number of terms in the expansion of `(1+6x+9x^2)^(23)`

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To find the number of terms in the expansion of \((1 + 6x + 9x^2)^{23}\), we can follow these steps: ### Step 1: Rewrite the expression We start with the expression \((1 + 6x + 9x^2)^{23}\). We can recognize that \(9x^2\) can be expressed as \((3x)^2\). Thus, we can rewrite the expression as: \[ (1 + 6x + (3x)^2)^{23} \] ### Step 2: Identify the form Now, we can see that the expression is in the form of \(a + b + c\), where: - \(a = 1\) - \(b = 6x\) - \(c = 9x^2\) ### Step 3: Use the multinomial theorem According to the multinomial theorem, the number of distinct terms in the expansion of \((a + b + c)^n\) is given by the formula: \[ \frac{(n + k - 1)!}{(k - 1)!n!} \] where \(n\) is the exponent and \(k\) is the number of different terms. In our case: - \(n = 23\) - \(k = 3\) (since we have three terms: \(1\), \(6x\), and \(9x^2\)) ### Step 4: Calculate the number of terms Using the formula, we find the number of distinct terms: \[ \text{Number of terms} = \frac{(23 + 3 - 1)!}{(3 - 1)! \cdot 23!} = \frac{25!}{2! \cdot 23!} \] ### Step 5: Simplify the expression Now we can simplify: \[ \frac{25!}{2! \cdot 23!} = \frac{25 \times 24}{2 \times 1} = \frac{600}{2} = 300 \] ### Step 6: Conclusion Thus, the number of distinct terms in the expansion of \((1 + 6x + 9x^2)^{23}\) is: \[ \boxed{300} \]
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ICSE-SAMPLE QUESTION PAPER 02-SECTION B
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