In the following reaction, 'X' refers to the compound:
`HCHO+CH_(3)MgI underset("ether")overset("dry")to "Intermediate" underset(H^(+)//H_(2)O) overset(HCl)to 'X'`

Options

A. `CH_(3)OH`
B. `CH_(3)CH_(2)OH`
C. `CH_(3)COCH_(3)`
D. `CH_(3)OCH_(3)`

Explanation

To solve the question, we need to analyze the given reaction step by step.

### Step 1: Identify the Reactants
The reaction involves formaldehyde (HCHO) and a Grignard reagent, which is methylmagnesium iodide (CH3MgI). The solvent used is dry ether.

### Step 2: Understand the Grignard Reaction
Grignard reagents react with carbonyl compounds (like aldehydes and ketones) to form alcohols. In this case, HCHO (formaldehyde) will react with CH3MgI.

### Step 3: Reaction Mechanism
1. The carbon atom in HCHO is electrophilic due to the presence of the carbonyl group (C=O).
2. The nucleophilic carbon from the Grignard reagent (CH3-) attacks the electrophilic carbon in HCHO.
3. This forms a tetrahedral intermediate where the oxygen atom of the carbonyl group becomes negatively charged (alkoxide ion).

### Step 4: Formation of the Intermediate
The reaction can be represented as:
\[ \text{HCHO} + \text{CH}_3\text{MgI} \rightarrow \text{H}_2\text{C(OH)(CH}_3)\text{MgI} \]
This intermediate has a structure where:
- The carbon is now bonded to a hydroxyl group (-OH) and a methyl group (-CH3).

### Step 5: Hydrolysis of the Intermediate
Next, we treat this intermediate with H+ and H2O (acidic hydrolysis):
1. The alkoxide ion (O-) will react with water.
2. The magnesium iodide bond will break, and the oxygen will get protonated (H+ from HCl).
3. This results in the formation of an alcohol.

### Step 6: Identify the Product
The final product after hydrolysis will be:
\[ \text{CH}_3\text{CH}_2\text{OH} \]
This compound is ethanol.

### Conclusion
The compound 'X' formed in the reaction is ethanol (CH3CH2OH).

### Answer
Thus, the answer is:
**X = CH3CH2OH (Ethanol)**