The reaction `C_(2)H_(5)ONa +C_(2)H_(5)I to C_(2)H_(5)OC_(2)H_(5)+Nal` is called

Options

A. Hoffmann's reaction
B. Williamson synthesis
C. Wurtz synthesis
D. Kolbe synthesis

Answer

To determine the name of the reaction given by the equation:

\[ C_2H_5ONa + C_2H_5I \rightarrow C_2H_5OC_2H_5 + NaI \]

we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Sodium ethoxide (\(C_2H_5ONa\))
- Iodoethane (\(C_2H_5I\))

### Step 2: Identify the Products
The products formed from this reaction are:
- Diethyl ether (\(C_2H_5OC_2H_5\))
- Sodium iodide (\(NaI\))

### Step 3: Understand the Reaction Type
This reaction involves the formation of an ether from an alkoxide and an alkyl halide. Specifically, sodium ethoxide (an alkoxide) reacts with iodoethane (an alkyl halide) to produce diethyl ether.

### Step 4: Name the Reaction
This type of reaction is known as the Williamson synthesis. The Williamson synthesis is a well-known method for the preparation of ethers through the reaction of an alkoxide with an alkyl halide.

### Conclusion
Thus, the reaction \(C_2H_5ONa + C_2H_5I \rightarrow C_2H_5OC_2H_5 + NaI\) is called **Williamson synthesis**.