Diethyl ether on heating with excess of HI yields

Options

A. `C_(2)H_(5)OH`
B. `C_(2)H_(5)I`
C. `C_(2)H_(4)`
D. `C_(2)H_(6)`

Explanation

To solve the question of what diethyl ether yields when heated with excess HI, we can follow these steps:

### Step 1: Write the Structural Formula of Diethyl Ether
Diethyl ether is represented by the formula C2H5OC2H5. Its structural formula can be depicted as:

```
H H
\ /
C
/ \
H - C O - C - H
\ /
H
H H
```

### Step 2: Understand the Reaction with HI
When diethyl ether is heated with excess hydrogen iodide (HI), the ether undergoes cleavage. The C-O bond in the ether is broken due to the strong acidic nature of HI.

### Step 3: Break the C-O Bond
The reaction involves breaking the C-O bond, which results in the formation of two ethyl iodide (C2H5I) molecules. The reaction can be represented as:

\[ \text{C2H5OC2H5} + 2 \text{HI} \rightarrow 2 \text{C2H5I} + \text{H2O} \]

### Step 4: Identify the Products
From the reaction, we can see that the products formed are:
- **2 molecules of Ethyl iodide (C2H5I)**
- **1 molecule of Water (H2O)**

### Final Answer
Thus, when diethyl ether is heated with excess HI, it yields:
- **2 C2H5I (Ethyl iodide)**
- **1 H2O (Water)**